find two numbers such that,one of them is equal is 8 more than the other and their sum is equal to 64? please tell with steps
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find two numbers such that,one of them is equal is 8 more than the other and their sum is equal to 64? please tell with steps
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Then, the other number would be X+8
Their sum given, 64
That means, X+X+8 =64
2X+8=64
2X=56
X=28
Other number is X+8=28+8=36