find value of k if x-1 is factor of p(x) in following cases 1) p(x) = kx square -root2x + 1 2) p(x) =kx square-3x+k
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find value of k if x-1 is factor of p(x) in following cases 1) p(x) = kx square -root2x + 1 2) p(x) =kx square-3x+k
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Answer:
x- 1=0
x=1
kx^2-√2x+12=0
k(1)^2-√2(1)+12=0
k-√2+12=0
k=√2-12
x -1=0
x=1
kx^2-3x+k=0
k(1)^2-3(1)+k=0
k-3+k=0
2k-3=0
k=3/2