Find x and y in the following figure
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Given it is an Isoceles ∆
So y=(180°-120°=60°
x=120°-60°=60°(exterior angle prpty)
(2)
it is a Right angled Isoceles Triangle..
So x=45°(Since the isoceles sides make an Angle Of 90° at the point of their Incidence)
Now y=x+90°=45°+90°=135°(Exterior angle Prpty.)
(3)
Here Y=x+92°
But it is also and isoceles ∆,
And by angle sum Prpty of a ∆,
x+x+92°=180°
→2x=180°-92°=88°
→x=44°
So Y=44°+92°=136°
Hope you understand...
Regards,
Leukonov.
Hits The comments..If you have Further Doubts.