find zero
1. x²+12x+27
2. 3x²+7x+4
3. x²-2x-63
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Answer:
1) -9 and -3
2) -4/3 and -1
3) -7 and 9
Step-by-step explanation:
1)
x²+12x+27 = 0
x²+9x+3x+27 = 0
x(x+9)+3(x+9) = 0
(x+9)(x+3) = 0
Either x+9 = 0, so x = -9
Or x+3 = 0, so x = -3
2)
3x²+7x+4=0
3x²+4x+3x+4=0
x(3x+4)+1(3x+4)=0
(3x+4)(x+1)=0
Either 3x+4=0, so x = -4/3
Or x+1=0, so x = -1
3)
x²-2x-63=0
x²+7x-9x-63=0
x(x+7)-9(x+7)=0
(x+7)(x-9)=0
Either x+7=0, so x = -7
Or x-9=0, so x = 9
Verified answer
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Step-by-step explanation:
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