find zeros of polynomial of 4u²+ 8u
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find zeros of polynomial of 4u²+ 8u
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Answer:
zeros of this polynomial( 4u²+ 8u) will be ,
0, -4
Step-by-step explanation:
4u²+ 8u = 4u( u+2)=0
(4u+0)(u+2)
u = -2,0