Five years ago a man was seven times as old as his son. Five years hence, the man will be three
times as old as his son. Find their present ages.
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Five years ago a man was seven times as old as his son. Five years hence, the man will be three
times as old as his son. Find their present ages.
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Answer:
present age of father is 40 and son is 10
Step-by-step explanation:
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years