five years ago nuri was thrice as old as Sony. ten years ago, nuri will be twice as old as sonu. how old are nuri and sonu.
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five years ago nuri was thrice as old as Sony. ten years ago, nuri will be twice as old as sonu. how old
five years ago nuri was thrice as old as Sony. ten years ago, nuri will be twice as old as sonu. how old are nuri and sonu.
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Answer:
Step-by-step explanation:
let the present age of nuri be:x
and present age of sonu be :y
according to the question
x-5=3(y-5)
3y-x-10=0 (eqn 1)
also given in the question:
x+10=2(y+10)
2y -x +10=0 (eqn2)
subtract eqn 2 from eqn 1 we get :
y-20=0
hence y=20
subsitute value of y in eqn 1 we get
x=50
hence age of nuri:50 yrs
age of sonu:20 yrs
Step-by-step explanation:
Let age of Nuri = X
Let age of Sony = Y
First, five years ago (-5)
x - 5 = 3(y-5)
x - 5 = 3y - 15
x = 3y - 10
3y - x = 10 (i)
Now ten years ago,
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x = 2y + 20 - 10
x = 2y + 10
2y - x = - 10 (ii)
Now solve for X and then using that find the age of Sonu.