For the polynomial p(x)=x^(5)+4x^(3)-5x^(2)+x-1 one of the factors is
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For the polynomial p(x)=x^(5)+4x^(3)-5x^(2)+x-1 one of the factors is
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x-1 is a factor of the given polynomial
Step-by-step explanation:
x-1 = 0
=> x = 1
Substitute x in the given polynomial ..
[tex]x^5+4x^3-5x^2+x-1[/tex]
[tex]{\implies{1^5+4(1)^3-5(1)^2+1-1}}[/tex]
[tex]{\implies{1+4-5+1-1}}[/tex]
[tex]{\implies{0}}[/tex]
[tex]{\therefore {x-1=0\ is\ a\ factor\ of\ the\ given\ polynomial }}[/tex]