Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced?
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CLASS - XI PHYSICS (Laws of Motion)
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Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced?
please do not post copied answers
CLASS - XI PHYSICS (Laws of Motion)
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Answer:
16N and 12N are acting in mutually perpendicular direction.
So resultant force = v(162 + 122) = v 256+144
= V400 = 20N
mass of body = 200 kg
acceleration = net force/mass = 20/200 = 0.1 m/s2