formed.
A
13. In the given figure, ABCD is a rectangle in which AB = 26 cm
and AD = 45 cm. Also, BEC is a right triangle in which ZDEC
= 90° and BE = 10 cm. Find the area of the shaded portion.
B
С
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formed.
A
13. In the given figure, ABCD is a rectangle in which AB = 26 cm
and AD = 45 cm. Also, BEC is a right triangle in which ZDEC
= 90° and BE = 10 cm. Find the area of the shaded portion.
B
С
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Answer:
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Answer:
Clearly, DC = AB = 26 cm.
Now, in right triangle DEC, we have:
DE = √DC – CE = √(26) – (10)
= √(26 +10)(26 - 10) cm = √36 x 16 cm
= (6 x 4) cm = 24 cm.
- Area of ∆DEC
[tex] \frac{1}{2} \times DE × CE[/tex]
[tex]( \frac{1}{2} \times 24 \times 10)cm {}^{2} = 120cm {}^{2} [/tex]
Area of rect. ABCD = (45 x 26) cm² = 1170 cm².
:. Area of the shaded region
= (area of rect. ABCD) - (area of ADEC)
= (1170 - 120) cm²= 1050 cm²
more to know.