Four identical particles each of mass 1kg are arranged at the corners of a square of side length 2√2m.If one of the particles is removed,the shift in the centre of mass is
Share
Four identical particles each of mass 1kg are arranged at the corners of a square of side length 2√2m.If one of the particles is removed,the shift in the centre of mass is
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
2/3
Explanation:
Before the removal of any one particle, all four are considered,
Xcom=M1X1+M2X2+M3X3+M4X4 / M1+M2+M3+M4
=1*0+1*0+1*2root2+1*2root2 / 1+1+1+1
=2root2+2root2 / 4 = 4root2 / 4 = root2
Ycom = M1Y1+M2Y2+M3Y3+M4Y4 / M1+M2+M3+M4
= 1*0+1*0+1*2root2+1*2root2 / 1+1+1+1
= 2root2+2root2 / 4 = 4root2 / 4 = root2
After removal of one point,
Xcom=M1X1+M2X2+M3X3 / M1+M2+M3
=0*1+1*0+1*2root2 / 1+1+1
=2root2/3
Ycom = M1Y1+M2Y2+M3Y3 / M1+M2+M3
= 1*2root2+0*1+1*0 / 1+1+1
= 2root2/3
The shift in the centre of the mass is,
=
=2/3