Four years ago A age was 3 times B age. After 8 years A age will be twice B. Then the sum of their present ages is
Share
Four years ago A age was 3 times B age. After 8 years A age will be twice B. Then the sum of their present ages is
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Given :
Given that, four years ago, A was 3 times B age and after 8 years, A will be twice B.
To find :
We have to find the sum of their present ages.
Solution :
Let the ages of A and B be x and y respectively.
From the question, four years ago :
Also, after 8 years :
Now, solving the equations 1 and 2 :
Substituting equation 3 in equation 2 :
Substituting y = 16 in equation 3 :
Finding the sum of their ages :
_________________________
Therefore, the sum of the present ages of A and B is 56 years.
Answer:
a+b =56 years hence it is confirmed