From a bridge, 25m high the angle of depression of a boat is 45 degrees. Find the horizontal distance of the boat from the bridge.
Share
From a bridge, 25m high the angle of depression of a boat is 45 degrees. Find the horizontal distance of the boat from the bridge.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
25m
Step-by-step explanation:
Let the angle B be 45 degree (Angle of depression)
when B is 45 degree then angle A will also be 45 degrees.
Let a be the height of the bridge=25 m(given)
Let b be the distance from the boat to the bridge.
therefore tan teta=opposite side/adjacent side .(teta=45degrees) tan 45 degree= a/b
(tan 45 degree=1) --(standard unit)
then tan 45 degrees = a/b
= 1 =25/b
therefore on solving , b=25m which is the distance from boat to the bridge.
(A suggestion: plz draw a line horizontal to the angle B which is not present in the picture attached to this)(then the angle of depression in this question would be between the horizontal line drawn and the side c.) (neglect side c in solving this question)
Hope it helps:)