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Answer:
Equblirium Temprature is 6.67°C
Explanation:
Given :- 1kg of ice at - 10°C is mixed with 1 kg water at 100°C .
Let the final temprature be T
Here, Heat lost by 1kg water = Heat energy needed to change the temperature of ice from –10°C to 0°C + Latent heat needed to change ice at 0°C into water at 0°C + heat absorbed by water (melted ice)
⟹m₁s₁ (T₁-T) = m₂ s₂ (0- T₂ ) + m₂L + m₂s₂ (T-T₂)
⟹1×1 (100-T) = 1 × 1/2 ×10 + 1 × 80 + 1 × 1/2(T+10)
⟹100-T = 5 + 80 + T/2/ +5
⟹ 10 = T/2+T
⟹ 10 = 3T /2
T = 20/3 = 6.67°C (Approax )Answer