from the given table answer the following :please give me answer as soon as possible....
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from the given table answer the following :please give me answer as soon as possible....
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Electrons present in e are : 4
C is a inhert gas because it has completely full electrons in it's outermost shell
Atom b will form negative ion
Element d has 12 neutrons as atomic mass = no. of protons + no. of neutrons
And no. of protons = no. of electrons
23= 11- no. of neutrons
= 12
A). Electrons present in E.
Mass no. = 9
Atomic no. = 4
Thus, atomic no. = Mass no. - no. of neutrons
4 = 9 - no. of neutron
No. of neutron = 9-4=5
Therefore,
Proton + neutron = mass no
Proton + 5=9
Proton= 4
This no.of electron = no.of proton =4
B) c is an inert gas because it has atomic no. 2 and has valency 0. Those elements having valency 0 are inert gas
C). B will form negative charged ions because it has electronic configuration 2,7 as it's atomic no. is 9. Thus to complete it's shell it needs one electron . Thus gaining of electron forms negative charge.
D). D has 12 neutrons because
Atomic no. = Mass no. - no. of neutrons
D= 23-11=12
E). D will form a positive charge as it has electronic configuration 2,8,1 because of its atomic no. 11. Thus to complete it's shell it will loose 1 electron which makes it positively charged.