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Answer:
2 - 28 mL
Explanation:
See the attachment for details
Answer:
(1) 5.61 ml
Explanation:
First let us know what happens when we mix KMnO4 with H2O2 in acidic medium.
2KMnO4+ 5H2O2+ 3H2SO4 → 5O2+ 2MnSO4+ K2SO4+ 8H2O
» 2 moles of KMnO4 releases 5 moles of O2
» 1 mole of KMnO4 releases 2.5 moles of O2
Given, 50 ml of 0.2M KMnO4
no.of.moles = Molarity × Volume in liters
no.of.moles = 0.2×1/(50/1000)
= 0.001 moles
» 0.001 moles of KMnO4 releases 0.0025 moles of O2
» 1 mole ----> 22400ml
» 0.0025 mole ----> 56ml of O2
To release 56 ml of O2, 56ml of 1V H2O2 is req or 5.6ml of 10V H2O2 is required.
Hence 5.6ml of 10V H2O2 is required.