17. A body is projected with the speed v at
an angle of 45 ° with
respect to the Earth. What is the range of
the body?
v/g
V2v/g
v*v/g
2v*v/g
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Answer:
ans will be v*v/g
Explanation:
range= u sq sin2theta/g
u=v, sin 2 theta=sin 90=1
hence range= v sq /g