give me solution please
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Given:- AB= 3cm , BC = 4cm , CD= 6cm, DA= 5cm and diagonal, AC= 5cm.
Area of ∆ ABC
S is the half perimeter
S= 3+4+5 /2
S= 12/2 = 6cm
= √S(s-a)(s-b)(s-c)
= √6(6-3)(6-4)(6-5) cm²
= √6x3x2x1 cm²
= √36 cm²
= 6 cm²
Now, Area of ∆ ADC,
S= 5+6+5/2
S= 16/2 = 8cm
= √s(s-a)(s-b)(s-c)
= √8(8-5)(8-6)(8-5)
= √8x3x2x3
= √144 cm²
= 12 cm²
Now Area of Quadrilateral= Area of ∆ ABC + Area of ∆ ADC
Area of Quadrilateral= (6+12) cm²
Hence, Area of Quadrilateral= 18cm²
⭐Be Brainly⭐