Given, → m₁ = 2kg M₂=2kg F=1N r=?
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Answer:
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Explanation:
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Answer:
Let the acceleration of the blocks be a.
The free-body diagrams for both blocks are shown below.
From the free-body diagram
m1 a=m 1
g+F−T.......(i)
Again from the free-body diagram,
m 2a=T−m 2 g−F......(ii)
Adding equations (i) and (ii) we have
a=g m 1 +m 2m 1 −m 2
⇒a= 7 3g= 7 29.4=4.2m/s
2
Hence, the acceleration of the block is 4.2m/s
2
After the string breaks, m
1
moves downwardss with force F acting downward. Then,
m
1
a=F+m
1
g
5a=1+5g
⇒a=
5
5g+1
=g+0.2m/s
2
Explanation: