Given : specific resistance, where r is the radius of a wire, l is the length of the wire and R is the resistance of the wire. Calculate the percentage error in , if R = (64 ± 2) ohm; l = (156.0 ± 0.1) cm, r = (0.26 ± 0.02) cm
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Given : specific resistance, where r is the radius of a wire, l is the length of the wire and R is the resistance of the wire. Calculate the percentage error in , if R = (64 ± 2) ohm; l = (156.0 ± 0.1) cm, r = (0.26 ± 0.02) cm
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Answer:
r = radius of the wire = (0.26 ± 0.02) cm, l = length of the wire = (156.0 ± 0.1) cm
R = resistance of the wire = (64 ± 2) ohm
Explanation:
r = radius of the wire = (0.26 ± 0.02) cm, l = length of the wire = (156.0 ± 0.1) cm
R = resistance of the wire = (64 ± 2) ohmA 35 Ω resistor is placed across potential difference of 0.22kV. Find the current drop across that resistor. If the voltage now reduced to 0.11kV.