Find the area of Parallelogram ABCD if three of its vertices areA (2,4) B (2+ ROOT 3 , 5 ) and C (2,6).<br />please solve it on a paper I'll surely mark the best answer as brainlist and even follow you
Find the area of Parallelogram ABCD if three of its vertices areA (2,4) B (2+ ROOT 3 , 5 ) and C (2,6).<br />please solve it on a paper I'll surely mark the best answer as brainlist and even follow you
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Thank you for asking this question. Here is your answer:
If there is a diagonal in a parallelogram it bisects into two equal triangles:
which will be:
ar(llgm ABCD) = 2ar (ΔABC) -- (this will be an equation 1)
The area of triagnle with the vertices (x₁,y₁),(x₂,y₂) and (x₃,y₃)
= 1/2 [x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)]
Area of ΔABC = 1/2 [2(5-6) + (2+√3) (6-4) + 2(4-5)]
= 1/2 [-2 + 4 + 2√3-2]
= 1/2 (2√3)
= √3
so ar(llgm ABCD) = 2ar (ΔABC)
= ar(llgm ABCD) = 2 x √3
= 2√3 is the final answer for this question.