Guys Anyone solve this problem
Sub :- Physics NCERT
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Guys Anyone solve this problemSub :- Physics NCERT
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SOLUTION :-
a) The distance covered by the moving object is calculated as follows:
AB + BC + CD + DE + EF
3 + 1 + 1.5 + 0.5 + 0.5 = 6.5 km
The distance covered by the moving object is 6.5 km.
b) The initial point is A and the final point is F, hence the magnitude of the displacement is equal to the distance AF which is calculated by applying Pythagora’s theorem to the triangle AHF as shown in the attachment.
Applying the Pythagorean formula, we get
AF²=AH²+HF²
Substituting the formula, we get
AF² = (0.5×4)² +(0.5×3)²
AF² = 6.25
AF = √6.25
.°. AF = 2.5 km.
The magnitude of displacement is 2.5 km.
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Answer:
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