guys please answer this question
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Hey mate !u = 40 m/sec
g = 10 m/sec²( in opposite directions symbol '-' use)
time taken to react the top most point is "t''
we have a formula
v = u - at
0 = 40 - (10)t
-40 = -10 t
t = 4 sec
Distance travelled in 4 sec
S1 = ut + 1/2 at²
=> 40 × 4 - 0.5 × 10 × 4²( upward direction g in negative)
=> 80m
a) in 2 sec
in this initial velocity becomes zero because particle came in downward direction and gravity pulls this ( '+')
here time is less we will taking it -2 sec or 2 sec
S2 = ut + 1/2 at²
= 0×2 - 1/2 (10)(2)²
= 0 - 1/2 × 10×4
= -1/2 (40)
= -20 m ( or 20 m )
Total distance is 80+(-20) = 60m
Net displacement is 80-20 = 60 m
b) 4 sec
Difference of time = 4-4 = 0 sec
S3 = ut + 1/2 at²
= 0×0 + 1/2 ( 10) (0)²
= 0 m
Total Distance = 80m - 0m
= 80 m
Displacement = 80 m
c) 6 sec
Difference of time = 6 sec - 4 sec
=> 2 sec
S4 = ut +1/2 at²
=0 + 1/2 (10)(2)²
= 1/2(40)
= 20 m
Total distance = 80+20 = 100 m
Net displacement = 80-20 = 60 m