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Answer:
Let first term be a
c.d.of first and second A.Ps be D1 and D2 respectively.
7th term= 23 and 21th term= 125
So,a+6d1= 23
a= 23-6d1 (eq.1)
a+20d2=125
a= 125-20d2 (eq.2)
from eq.1and2 we get,
23-6d1=125-20d2
20d2-6d1= 102
10d2-3d1= 51. (eq.3)
but D1:d2= 1:2
d2=2d1
from eq.3
20d1-3d1=51
17d1=51
D1=3
d2=6
a+18=23
a=5
So,two a.ps are 5,8,11,14......
and 5,11,17,23.....
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