An aeroplane is flying horizontally with a velocity
of 600 km/h and is at a height of 1960 m. When it
is vertically at a point A on the ground, a bomb is
released from it. The bomb strikes the ground at
point B. The distance AB is -
1) 33km 2) 1200m 3) 3.33km 4) 0.33km
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Explanation:
The velocity with which the bomb is released is 600km/h(horizontal).
Vertical velocity of the bomb is zero.
So.distance AB=600
18
5
∗t t is the time taken by the bomb to reach the ground.
1960=g
2
t
2
which gives AB equal to 3.3.km.