4)A train travels at a speed of 58km/h for 0.5 hour ,46km/h for the next 0.25hour and then at 70km/h for the next 0.75 hour. Calculate the total distance covered by the train and its average speed.
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4)A train travels at a speed of 58km/h for 0.5 hour ,46km/h for the next 0.25hour and then at 70km/h for the next 0.75 hour. Calculate the total distance covered by the train and its average speed.
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Answer:
Explanation:
Given,
To find,
so,
Using formula
Calculating Distance covered by train when it travels at 58 km/h for 0.5 hour
→ d₁ = 58 × 0.5
→ d₁ = 29 km
Calculating Distance covered by train when it travels at 46 km/h for 0.25 hour
→ d₂ = 46 × 0.25
→ d₂ = 11.5 km
Calculating Distance covered by train when it travels at 70 km/h for 0.75 hour
→ d₃ = 70 × 0.75
→ d₃ = 52.5 km
▶ Calculating total distance covered by the Train
→ d = d₁ + d₂ + d₃
→ d = 29 + 11.5 + 52.5
→ d = 93 km
therefore,
Now,
Using formula
→ Average speed = ( 93 ) / ( 0.5 + 0.25 + 0.75 )
→ Average speed = 93 / 1.5
→ Average speed = 62 km/h
therefore,
Verified answer
Answer :
A train travels at a speed of 58km/h for 0.5h, 46km/h for the next 0.25h and then at 70km/h for the next 0.75h.
We have to find the total distance covered by the train and it's average speed
_________________________________
◈ Total distance covered by the train :
We know that speed is defined as the ratio of distance travelled to the time taken.
d = d₁ + d₂ + d₃
d = v₁t₁ + v₂t₂ + v₃t₃
d = 29 + 11.5 + 52.5
d = 93 km
◈ Average speed of train :
Average speed of body is defined as the ratio of total distance travelled to the total time taken.
It is a scalar quantity having only magnitude.
SI unit : m/s
➝ Vav = d / (t₁ + t₂ + t₃)
➝ Vav = 93 / (0.5+0.25+0.75)
➝ Vav = 93/1.5
➝ Vav = 62 km/h