A stone is thrown upwards with a velocity of 72 km/h. If air resistance is
neglected, find the maximum height travelled by it and the time taken for it to
return to the initial position.
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A stone is thrown upwards with a velocity of 72 km/h. If air resistance is
neglected, find the maximum height travelled by it and the time taken for it to
return to the initial position.
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Answer:
converting speed into m/s =72*5/18=20 m/s
v^2=2gh
20*20=2*10*h
h=20m (maximum height)
v=gt
20=10*t
t= 2s time for upward motion
totaol time(upward+downward)=2+2=4s
Answer:
soln
Explanation:
speed(v)=72km/h
=72*1000m/60*60s{to convert in meter per second}
=20m/s
now
v^2=2gh
(20)^2=2*10*h
400=20h
h=20m
again
v=gt
20=10*t
t=2s{only upward motion}
so
total time(upward+downward)= 2s+2s
= 4s