If a car accelerates uniformly from rest and attains a speed of 40km/h in 10 second, how much distance it covers?
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initial velocity (u) = 0 m/s
final velocity (v)= 40m/s
time = 10 seconds
now,
acceleration= (v-u)/t
= 40-0/10
= 4 m/s
now using the third equation of motion,
v^2-u^2=2as
(40)^2-0= 2×4×s
s= 40×40/2×4
= 200 m
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