a swimming pool in a school is cuvoidal which is 50m long and 44m wide . It is connected with a pipe of diameter 14cm from where water is flowing into the pool at the rate of 15km/h. In what time will the level of water in the pool rise by 21cm..
a swimming pool in a school is cuvoidal which is 50m long and 44m wide . It is connected with a pipe of diameter 14cm from where water is flowing into the pool at the rate of 15km/h. In what time will the level of water in the pool rise by 21cm..
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Answer:
Time taken in which level of water in the pool rise is 2 hours.
Step-by-step explanation:
Given : A swimming pool in a school is cuvoidal which is 50m long and 44m wide . It is connected with a pipe of diameter 14cm from where water is flowing into the pool at the rate of 15km/h.
To find : In what time will the level of water in the pool rise by 21cm?
Solution :
Let the time in which the level of water rise by 21 cm be t hrs.
Diameter of pipe= 14cm
So, radius= 7cm = 0.07m
Rate (h)= 15 km/hr= 15000 m/hr
Volume of water flowing out in 1 h is
Now, If the volume of water flowing out in 1 hr is 231 m cube then the volume of water flowing out in t hrs will be 231 t m cube.
Volume of water flowing out in t hrs= Volume of cuboidal pool
Therefore, Time taken in which level of water in the pool rise is 2 hours.