half the perimeter of a rectanglular garden , whose length is 4 m more than its width 36m . find the dimensions of the garden
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half the perimeter of a rectanglular garden , whose length is 4 m more than its width 36m . find the dimensions of the garden
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perimeter =2 (l+b)
half peri. 36m= (l+b)
let breadth=x
length= 4x
perimeter= 2×36
= 72m
perimeter = 2 (l+b)
72= 2 (4+x+x)
36= 4+2x
36-4=2x
32= 2x
32/2=x
16=x
breadth=16
length= x+4=16+4=20
Verified answer
Question:-
half the perimeter of a rectanglular garden , whose length is 4 m more than its width 36m . find the dimensions of the garden
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Let the width of the garden =x meter
Then length=(x+4) meter
Half perimeter =36 m
So perimeter of garden =(2×36)=72 meters
According to the question
⇒2(l+b)=72
⇒2(x+x+4)=72
⇒2x+2x+4=74⇒4x=64⇒x=16 meters
Hence,the width of the garden =16 meters
The length of the garden =(16+4)=20 meters
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