Harendra singh sells two
aritcles at Rs. 1710 He sells
first article at 10% loss
while earn 25% profit on
second. If C.P of first article
is equals to S.P of second
article Find his profit or loss
on overall?
Share
Harendra singh sells two
aritcles at Rs. 1710 He sells
first article at 10% loss
while earn 25% profit on
second. If C.P of first article
is equals to S.P of second
article Find his profit or loss
on overall?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
[tex]\huge{\underline{\purple{\rm{Solution:}}}}[/tex]
[tex]\small{\underline{\red{\rm{Given\:in\:case\:1}}}}[/tex]
Selling price of 2 article=Rs.1710
Loss on 1st article=10%
profit on 2nd article=25%
[tex]\small{\underline{\red{\rm{Let:}}}}[/tex]
The cost price of 1st article=X
The cost price of 2nd article=Y
[tex]\small{\underline{\green{\rm{As\:per\:the\: above\: information:}}}}[/tex]
[tex]\small{\boxed{\red{\rm{SP=(\frac{100+G\%}{100})*CP:}}}}[/tex]
[tex]\sf{\dashrightarrow \frac{100-10}{100}*X+\frac{100+25}{100}*Y=1710}[/tex]
[tex]\sf{\dashrightarrow \frac{90}{100}*X+\frac{125}{100}*Y=1710}[/tex]
[tex]\sf{\dashrightarrow 0.9X+1.25Y=1710----(1)}[/tex]
[tex]\small{\underline{\red{\rm{Given\:in\:case\:2}}}}[/tex]
CP of 1st article is equal to SP of 2nd article
[tex]\sf{\dashrightarrow X=1.25Y----(2)}[/tex]
Putting the value of X=1.25Y in EQ 1
[tex]\sf{\dashrightarrow 1.25Y+1.25Y=1710}[/tex]
[tex]\sf{\dashrightarrow 0.9*1.25Y+1.25Y=1710}[/tex]
[tex]\sf{\dashrightarrow 1.125Y+1.25Y=1710}[/tex]
[tex]\sf{\dashrightarrow 2.375Y=1710}[/tex]
[tex]\sf{\dashrightarrow Y=720}[/tex]
Putting the value of Y=720 in EQ 2
[tex]\sf{\dashrightarrow X=1.25*720}[/tex]
[tex]\sf{\dashrightarrow X=900}[/tex]
Now, Calculate total SP and CP here
[tex]\sf{\dashrightarrow Total\:SP=1710}[/tex]
[tex]\sf{\dashrightarrow Total\:CP=900+720}[/tex]
[tex]\sf{\dashrightarrow Total\:CP=1620}[/tex]
NOTE:If Sp is greater than Cp than we get profit
[tex]\large{\boxed{\green{\rm{P=SP-CP}}}}[/tex]
[tex]\sf{\dashrightarrow Profit=1710-1620}[/tex]
[tex]\sf{\dashrightarrow Profit=90}[/tex]
Hence,
He will get profit of Rs.90 on overall.
Answer:
Selling price of 2 article=Rs.1710
Loss on 1st article=10%
profit on 2nd article=25%
\small{\underline{\red{\rm{Let:}}}}
Let:
The cost price of 1st article=X
The cost price of 2nd article=Y
\small{\underline{\green{\rm{As\:per\:the\: above\: information:}}}}
Aspertheaboveinformation:
Using formula here
\small{\boxed{\red{\rm{SP=(\frac{100+G\%}{100})*CP:}}}}
SP=(
100
100+G%
)∗CP:
\sf{\dashrightarrow \frac{100-10}{100}*X+\frac{100+25}{100}*Y=1710}⇢
100
100−10
∗X+
100
100+25
∗Y=1710
\sf{\dashrightarrow \frac{90}{100}*X+\frac{125}{100}*Y=1710}⇢
100
90
∗X+
100
125
∗Y=1710
\sf{\dashrightarrow 0.9X+1.25Y=1710----(1)}⇢0.9X+1.25Y=1710−−−−(1)
\small{\underline{\red{\rm{Given\:in\:case\:2}}}}
Givenincase2
CP of 1st article is equal to SP of 2nd article
\sf{\dashrightarrow X=1.25Y----(2)}⇢X=1.25Y−−−−(2)
Putting the value of X=1.25Y in EQ 1
\sf{\dashrightarrow 1.25Y+1.25Y=1710}⇢1.25Y+1.25Y=1710
\sf{\dashrightarrow 0.9*1.25Y+1.25Y=1710}⇢0.9∗1.25Y+1.25Y=1710
\sf{\dashrightarrow 1.125Y+1.25Y=1710}⇢1.125Y+1.25Y=1710
\sf{\dashrightarrow 2.375Y=1710}⇢2.375Y=1710
\sf{\dashrightarrow Y=720}⇢Y=720
Putting the value of Y=720 in EQ 2
\sf{\dashrightarrow X=1.25*720}⇢X=1.25∗720
\sf{\dashrightarrow X=900}⇢X=900
Now, Calculate total SP and CP here
\sf{\dashrightarrow Total\:SP=1710}⇢TotalSP=1710
\sf{\dashrightarrow Total\:CP=900+720}⇢TotalCP=900+720
\sf{\dashrightarrow Total\:CP=1620}⇢TotalCP=1620
NOTE:If Sp is greater than Cp than we get profit
Using formula here
\large{\boxed{\green{\rm{P=SP-CP}}}}
P=SP−CP
\sf{\dashrightarrow Profit=1710-1620}⇢Profit=1710−1620
\sf{\dashrightarrow Profit=90}⇢Profit=90
Hence,
He will get profit of Rs.90 on overall.