Hello guys !!
✨✨✨
Plz solve this.....
I will mark you as brainlist...
...
..
Fltu ki bkwas skttt mna hai..
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Hello guys !!
✨✨✨
Plz solve this.....
I will mark you as brainlist...
...
..
Fltu ki bkwas skttt mna hai..
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Given: r1 = 1 cm, r2 = 2.5 cm, h = 6 cm
l = √h² + (r2-r1)²
= √(6)² + (2.5-1)² cm
= √36 + 2.25 cm
= √38.25 cm
= 6.18cm
So,
External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)
= 22/7(r1+r2)l +2.22/7.r1
= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²
= 22/7 (3.5 × 6.18 +2) cm²
= 22/7 (21.63+2) cm²
= 22/7 × 23.63 cm²
= 519.86/7 cm²
= 74.26 cm²
plz mark as brainliest mate ^_^
I hope it will help you....