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Please solve this question
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Don't spam!!!!
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Explanation:
we know that , heat loss = heat gain .
maximum heat loss by copper
block = mSdT
= 2500g X 0.39jg - 1k - 1 x ( 500 -0) K
= 487,500 j = ML
now
487,500 j = ML
where M is the mass of ice melted and L is the latent heat fusion .
487,500j = M X 335 jg -1
M = 1455.22 , g = 1.45522 kg .
HOPE THIS WILL HELP MY DEAR FRIEND.
option (b) is your answer
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[tex]\mathfrak{The\:Answer\:is}[/tex]
Mass of the copper block, m = 2.5 kg = 2500 g
Rise in the temperature of the copper block, Δθ = 500°C
Specific heat of copper, C = 0.39 J g^–1 °C^–1
Heat of fusion of water, L = 335 J g^–1
The maximum heat the copper block can lose,
Q = mCΔθ
= 2500 × 0.39 × 500
= 487500 J
Let m1 g be the amount of ice that melts when the copper block is placed on the ice block.
The heat gained by the melted ice,
Q = m1L
∴ m1 = Q / L
= 487500 / 335
= 1455.22 g
Hence, the maximum amount of ice that can melt is 1.455 kg.
[tex]\boxed{Hope\:This\:Helps}[/tex]
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