hello plx explain this answer ...and correct full explaination
Share
hello plx explain this answer ...and correct full explaination
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
We have two intersecting circles with centres at O and O’ respectively. Let PQ be the common chord.
∵ In two intersecting circles, the line joining their centres is perpendicular bisector of the common chord.
∴∠OLP = ∠OLQ = 90° and PL = LQ
Now, in right ∆OLP, we have
PL² + OL² = 2
⇒ PL² + (4 – x)2 = 52
⇒ PL² = 52 – (4 – x)2
⇒ PL² = 25 -16 – x2 + 8x
⇒ PL² = 9 – x2 + 8x …(i)
Again, in right ∆O’LP,
PL² = PO‘² – LO‘²
= 32 – x² = 9 – x² …(ii)
From (i) and (ii), we have
9 – x² + 8x = 9 – x²
⇒ 8x = 0
⇒ x = 0
⇒ L and O’ coincide.
∴ PQ is a diameter of the smaller circle.
⇒ PL = 3 cm
But PL = LQ
∴ LQ = 3 cm
∴ PQ = PL + LQ = 3cm + 3cm = 6cm
Thus, the required length of the common chord = 6 cm.
Therefore
The length of the common chord = 6cm.
Answer:
hi bestie
Step-by-step explanation:
stay safe . be happy
.have a good day