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last .........xD
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Answer:
Given.,
X = 5-2root 6
Value of,
Root X = Root(5-2root6)
Baaki Yaar... Tu kar le...... xD
Given: [tex]x = 5 - 2 \sqrt{6} [/tex]
To Find: [tex]\sqrt{x}[/tex]
Solution:
[tex] \sqrt{x} = \sqrt{5 - 2 \sqrt{6} } \\ \sqrt{x} = \sqrt{3 + 2 - 2 \sqrt{6} } \\ \sqrt{x} = \sqrt{ { \sqrt{3} }^{2} + { \sqrt{2} }^{2} - 2( \sqrt{3} )( \sqrt{2} ) } \\ [/tex]
Using
[tex](x - y) ^{2} = {x}^{2} + {y}^{2} - 2xy[/tex]
[tex] \sqrt{x} = \sqrt{( \sqrt{3} - \sqrt{2}) ^{2} } \\ \sqrt{x} = \sqrt{3} - \sqrt{2} [/tex]
Hope it Helps. ^_^