Divide the following polynomials.
a) (a² + 15a + 56) by (a + 8)
b) (4z³ + 14z² + 6z) by (z + 3)
c) (10a³ - a² + 4a + 35) by (2a² - 3a + 5)
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a) ( a^2 + 15 a + 56 ) ÷ ( a +8 )
Quotient = ( a+ 7 )
Remainder = 0
b) ( 4z^3 + 14z^2 + 6z ) ÷ ( z + 3 )
Quotient = ( 4z^2 + 2z )
Remainde = 0
c) ( 10a^3 - a^2 +4a +35 ) ÷ ( 2a^2 - 3a +5)
Quotient = ( 5a +7 )
remainde = 0
Verified answer
Step-by-step explanation:
1)
[tex] \frac{ {a}^{2} + 15a + 56}{a + 8} = a + 7 \\ \\ 2) \\ \frac{4 {z}^{3} + 14 {z}^{2} + 6z }{z + 3} = 4 {z}^{2} + 2z \\ \\ 3) \\ \frac{10 {a}^{3} - {a}^{2} + 4a + 35 }{2 {a}^{2} - 3a + 5 } = 5a + 7[/tex]
see the attached photo for division
Hope you get your answer