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Here Is A Question For You Guys ♥️♥️
Please Help Me In This Question...
Simplest Answer Will Be Brainlest ✌️✌️☺️
@Shona...❣️❣️
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Verified answer
( 1 + cot Ф + tan Ф )( sin Ф - cos Ф )
⇒ ( 1 + cos Ф / sin Ф + sin Ф / cos Ф )( sin Ф - cos Ф )
⇒ ( sin Ф cos Ф + sin²Ф + cos²Ф )( sin Ф - cos Ф ) / sin Ф cos Ф
Use the expansion : ( a - b )( a² + ab + b² ) = a³ - b³
⇒ ( sin³Ф - cos³Ф )/ sin Ф cos Ф
So ( sin³Ф - cos³Ф ) / ( sec³ - cos³Ф ) ( sin Ф cos Ф )
⇒ ( 1/cosec³Ф - 1/sec³Ф ) / ( sec³Ф - cos³Ф ) ( sinФ cosФ )
⇒ ( sec³Ф - cos³Ф )/sec³Фcosec³Ф ) / ( sec³Ф - cos³Ф )( 1/cosecФ.1/secФ )
⇒ secФcosecФ / sec³Фcosec³Ф
⇒ 1 / sec²Фcosec²Ф
⇒ sin²Фcos²Ф