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find the perimeter of triangle if its area is 9 cm^2 and perpendicular ² + breadth² is 45.
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✨✨Hey Brainiacs! ✨✨
Solve this .....
find the perimeter of triangle if its area is 9 cm^2 and perpendicular ² + breadth² is 45.
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Answer:
Area of traingle = \frac {1}{2} Base * height
2
1
Base∗height
\implies⟹ 1/2 × base × height = 9
\implies⟹ base × height = 18
As , given
\implies⟹ perpendicular ² + base² = 45
\implies⟹ Apply, (P + B )² = p² + B² + 2B× H
\implies⟹ (P + B)² = 45 + 2(18)
\implies⟹ (P + B)² = 45 + 36
\implies⟹ (P + B)² = 81
\implies⟹ (P + B) = √81 = 9
\implies⟹ So, Here we have to check the digits which makes sum 9
➡ 6 and 3 = 9
\implies⟹ Probably 6 and 3 are its base and perpendicular of the traingle.