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Find the sum of the first 40 positive integers divisible by 6?
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Hey
Find the sum of the first 40 positive integers divisible by 6?
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a = 6
Last term = a40 = 40*6 = 240
this series is an A.P
6,12,.............240
we know that
sum = n/2 ( first term + last term)
sum = 40/2 ( 6 + 240)
sum = 20*( 246)
sum = 4920 ans