Hey guys!!Can anyone solve this question???
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Hey guys!!Can anyone solve this question???
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[ For answer refer to attachment : ]
More to Know :-
The three equⁿs of motion are :-
A shortcut to do this type of question:-
When like in above question it is asked that after what time they will meet , then just divide the total height by the velocity by which the object from ground was projected.
Here h = 40m and v = 40m/s.
So , the time after which they met will be (40m÷40m/s) = 1s.
Wasn't that easy?