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hey mates
please answer this question
quality answers will be marked as brainliest
orelse reported
once again saying only quality answers with brief explanation will be marked as brainliest
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AnswEr :
From the Question,
Total mass of the system would be : 10 + 4 + 2 = 16 Kg
Here,
F₁ & sine of F₂ are acting downwards and F₃ is acting upwards.
Thus, Net Force and Acceleration are pointing downwards.
Now,
Therefore,
Net Force = F₁ + F₂ - F₃
[tex]\longrightarrow[/tex] Net Force = 10g N
[tex]\longrightarrow[/tex] Ma = 10g
[tex]\longrightarrow [/tex] 16a = 10 g
[tex]\longrightarrow[/tex] a = 5g/8
Acceleration of the system is 5g/8.
Verified answer
Given :
To find :
SoIution :
At first we need to find force on seperate bIocks i.e. [tex]\sf m_1, \ \sf m_2, \ \sf m_3[/tex] :
AppIying 2nd Iaw of Newton :
[tex]\longmapsto\sf Force = Mass \times AcceIeration[/tex]
[tex]\longmapsto\sf F_1 = mg = 10 \times g = 10g \ N [/tex]
[tex]\longmapsto\sf F_2 = mg\sin\theta \\ \longmapsto\sf F_2 = 4 \times \ g \times \sin 30 \degree \\ \longmapsto\sf F_2 = 4 \times \ g \times (1/2) \\ \longmapsto\sf F_2 = 2g \ N[/tex]
[tex]\longmapsto\sf F_3 = mg = 2 \times g = 2g \ N[/tex]
Now net force = [tex]\sf F_1 + F_2 - F_3[/tex]
Again net force, [tex]\sf F_{net} [/tex] = [tex](\sf m_1 + m_2 + m_3) \times a[/tex]
⇒ 10g + 2g - 2g = (10 + 4 + 2) × a
⇒ 10g = 16a
⇒ a = 10g/16
⇒ a = 5g/8 m/s²
∴ Correct option : 3)5g/8 m/s²