hey mates please solve this problem. it's urgent please please refrain from posting meaningless answer
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hey mates please solve this problem. it's urgent please please refrain from posting meaningless answer
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Step-by-step explanation:
Sin£ = perpendicular/hypotenuse
So, sin£=5/13
Now for tan theta:
Draw a straight line joining D and E(point on AB),
So as DC=5 so EB=5
And AB is 14
So 14-5=9
Length of AE=9
Now length of BC=length of DE
DE=12
NOW,tan theta=perpendicular/base
So, tan theta=12/9=4/3
Ans(i)(a)=5/13
Ans(i)(b)=4/3
Now, by Pythagoras theorem,
AD^2=DE^2+AE^2
AD^2= 12^2+9^2
AD^2=144+81
AD^2=225
AD=_/225
AD=15
So,Ans(ii)=15