hey please tell fast
question 2 e
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Step-by-step explanation:
(9.1)^2 = (9.0 + 0.1)^2
by applying identity (a+b)^2 = a^2 + b^2+2ab
put a = 9 ,b= 0.1
= 9^2 + 0.1^2 +2×9×0.1
= 81+0.01+1.8
= 82.81 ( answer)
hope this will helpful.
Answer:
Using the identity:
(a+b)^2 = a^2 + b^2 + 2ab
(9.1)^2
= (9 + 0.1)^2
= (9)^2 + (0.1)^2 + 2×9×0.1
= 81 + 0.01 + 01.80
= 81 + 01.81
= 82.81
Step-by-step explanation:
Hope it helps you.....