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Verified answer
Correct Question :-- For what value of k , the roots of Equation x²-4x + k = 0 are real and Equal ?
Concept used :--
If A•x^2 + B•x + C = 0 ,is any quadratic equation,
then its discriminant is given by;
D = B^2 - 4•A•C
• If D = 0 , then the given quadratic equation has real and equal roots.
• If D > 0 , then the given quadratic equation has real and distinct roots.
• If D < 0 , then the given quadratic equation has unreal (imaginary) roots...
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Solution :--
In Given Equation, x² - 4x + k = 0, we have ,
→ A = 1
→ B = (-4)
→ C = k
Since, roots Are real and Equal, we can say that ,
→ D = B² - 4AC = 0
Putting values now , we get,
→ (-4)² - 4*1*k = 0
→ 16 = 4k
Dividing both sides by 4, we get,
→ k = 4 .
Hence, value of k is 4, than Roots of Equation are real and Equal.
Verified answer
Correct question: For what value of k, will the roots of the equation , will the equation have real and equal roots.
Given:
To find: The value of k.
Answer:
For finding the value of k, we can choose to solve it by equating it to its discriminant (D).
D = .
There are three conditions before doing so.
Back to the question, it says that the roots are real and equal. So the first condition (D = 0) will be used.
Let's first get a, b and c from the equation.