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The length of a roller is 91 cm and its radius is 30 cm. If it rotates 100 times, how many m sq. of land will be levelled???
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Hii friends
The length of a roller is 91 cm and its radius is 30 cm. If it rotates 100 times, how many m sq. of land will be levelled???
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Given length of a roller h = 91 cm.
Given radius r = 30 cm.
We know that curved surface area of the roller = 2πrh
= > 2 * (22/7) * (30) * (91)
= > 2 * 22 * 30 * 13
= > 17160 cm^2.
So, the area leveled in one rotation = 17160 cm^2.
Given that it rotates 100 times.
Then, Area levelled in 100 times = 100 * 17160 cm^2
= > 1716000 cm^2
= > 171.6 m^2.
Therefore, the area of the land leveled = 171.6m^2.
Hope this helps!
Verified answer
As roller is a cylinderh=91cm
r=30cm
Its curved surface area = 2πrh
= 2 × 3.14 × 30 × 91
= 17144.4 cm²
In one round it levells 17144.4cm²
In 100 rounds it will levell 17144.4×100 cm²
= 1714440 cm²