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plzzzz solve this problem
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Answer:
70/10^i+ 240/10^j is right answer ithink
Answer:
Calculate magnitude of vector B
Magnitude of vector B = sqrt(7^2 + 24^2) = sqrt(625) =25
Calculate unit vector of Vector A
Unit Vector A = Vector A/ Magnitude of A
Magnitude of A = sqrt(3^2 + 4^2) = sqrt(25) = 5
Hence Unit Vector A = (3i+4j)/5 = (3/5)i + (4/5)j
Calculating Vector magnitude of B and parallel to A
Required Vector Say C = Magnitude of B * Unit vector of A
Hence C = 25*((3/5)i+(4/5)j) =25*(3/5)i + 25*(4/5)j
C = 15 i + 20 j
Verify
Magnitude of Vector C = sqrt(15^2 + 20^2) =sqrt(625) = 25 = Magnitude of Vector B
Check angle of vector A and Vector C
Angle of Vector A = taninverse(4/3) = 53.1301 degrees
Angle of Vector C = taninverse(20/15) = taninverse(4/3) = 53.1301 degrees
Final answer :
Hence Vector C = 15i + 20j has direction of Vector A and magnitude of Vector B
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