hlo guys plz let me understnd this..or u have any other solution of it then plz post it... ♥️Brainlist ♥️
hlo guys plz let me understnd this..or u have any other solution of it then plz post it... ♥️Brainlist ♥️
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The answer seems to be of a different question altogether.
Use: v=u+at and put a=2cm/sec², u=0 and t=3 sec to get
v=6cm/sec=0.06m/sec as the velocity 3sec after start.
I think the question and answer are different so I will answer according to question u may check answer with your ncert book
solution is given at the last page
of the book
let initial velocity to be 0 as it is starting
acceleration 2cm/s² and time has given 3 sec
so by 1st eq of motion
v=u+at
v=0+2/100*3
100v=6
v=6/100=0.06m/s²