A bus is travelling at a speed of 60 km/hour. On seeing a boy 11 m ahead on the
road, the driver of the bus applies brakes and the bus stops at a distance of 10 m.
What is its retardation and how long does it take to come at rest?
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A bus is travelling at a speed of 60 km/hour. On seeing a boy 11 m ahead on the
road, the driver of the bus applies brakes and the bus stops at a distance of 10 m.
What is its retardation and how long does it take to come at rest?
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Answer:
a= (-14.45)m/s^2
t= 1.2 second.
Explanation:
HELLO DEAR,
Given : Initial speed of bus, u= 60km/h = 17 m/ s (approx)
Final speed of bus v= 0m/s
Distance to reach after retardation = 10m
To find retardation and time taken to came at rest.
Solution: By using Newtown equation v^2 = u^2 + 2as
(0)^2= (17)^2 + 2a×10
0 = 289 +20a
a= -289/20
a= -14.45 m/s^2
So, retardation ,a= (-14.45m/s^2)
By using Newtons equation
v=u+at
0= 17+ (-14.45)t
t= -17/-14.45
t= 1.2 second (approx)
I HOPE IT'S HELP YOU DEAR,
THANKS.
Answer:
hello this is maths subject not science