How many different inyegers exist between 10^6 and 10^7, the sum of whose digits is 2
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How many different inyegers exist between 10^6 and 10^7, the sum of whose digits is 2
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Step-by-step explanation:
6 integers starting with 1 with sum of digits equal to 2 and one integer starting with 2. Hence, a total of (6 + 1) = 7 integers.
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How many different positive integers exist between 10^6 and 10^7, the sum of whose digits is equal to 2? We can have 6 integers starting with 1 with sum of digits equal to 2 and one integer starting with 2. Hence, a total of (6 + 1) = 7 integers. The correct answer is b.