) How many grams of nitrogen is required to completely react with 54g of magnesium
to form magnesium nitride.
Share
) How many grams of nitrogen is required to completely react with 54g of magnesium
to form magnesium nitride.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
I think this was a right answer......
Explanation:
As per the equation, let us calculate the mole ratio.
N
2
+
3
H
2
→
2
N
H
3
As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.
In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.
We can set up the ratio;
28.01 g of
l
N
2
needs
6.048 g of
l
H
2
1 g of
l
N
2
needs
6.048
28.01
g of
l
H
2
50.0 g of
l
N
2
needs
6.048
×
50.0
28.01
l
g of
l
H
2
=
10.80 g of
l
H
2